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32448590489113 is a prime number
BaseRepresentation
bin1110110000011000001101…
…01101011010011000011001
311020220001111001200120121221
413120030012231122120121
513223114203131122423
6153002402055132041
76556222215213661
oct730140655323031
9136801431616557
1032448590489113
11a380408441957
123780907374021
131514b73052b56
1480273d4631a1
153b40e0421e5d
hex1d8306b5a619

32448590489113 has 2 divisors, whose sum is σ = 32448590489114. Its totient is φ = 32448590489112.

The previous prime is 32448590489099. The next prime is 32448590489123. The reversal of 32448590489113 is 31198409584423.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26304671500864 + 6143918988249 = 5128808^2 + 2478693^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32448590489113 is a prime.

It is a super-2 number, since 2×324485904891132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32448590489123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16224295244556 + 16224295244557.

It is an arithmetic number, because the mean of its divisors is an integer number (16224295244557).

Almost surely, 232448590489113 is an apocalyptic number.

It is an amenable number.

32448590489113 is a deficient number, since it is larger than the sum of its proper divisors (1).

32448590489113 is an equidigital number, since it uses as much as digits as its factorization.

32448590489113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29859840, while the sum is 61.

The spelling of 32448590489113 in words is "thirty-two trillion, four hundred forty-eight billion, five hundred ninety million, four hundred eighty-nine thousand, one hundred thirteen".