Base | Representation |
---|---|
bin | 1110110000011011101011… |
… | …01010101001001000000011 |
3 | 11020220020021210111212012202 |
4 | 13120031311222221020003 |
5 | 13223132011210042201 |
6 | 153003310514343415 |
7 | 6556316311121462 |
oct | 730156552511003 |
9 | 136806253455182 |
10 | 32450452034051 |
11 | a381183212147 |
12 | 378114688ab6b |
13 | 15150ab91112c |
14 | 80287879a9d9 |
15 | 3b419da85c6b |
hex | 1d8375aa9203 |
32450452034051 has 2 divisors, whose sum is σ = 32450452034052. Its totient is φ = 32450452034050.
The previous prime is 32450452034041. The next prime is 32450452034057. The reversal of 32450452034051 is 15043025405423.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32450452034051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32450452033996 and 32450452034014.
It is not a weakly prime, because it can be changed into another prime (32450452034057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16225226017025 + 16225226017026.
It is an arithmetic number, because the mean of its divisors is an integer number (16225226017026).
Almost surely, 232450452034051 is an apocalyptic number.
32450452034051 is a deficient number, since it is larger than the sum of its proper divisors (1).
32450452034051 is an equidigital number, since it uses as much as digits as its factorization.
32450452034051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288000, while the sum is 38.
Adding to 32450452034051 its reverse (15043025405423), we get a palindrome (47493477439474).
The spelling of 32450452034051 in words is "thirty-two trillion, four hundred fifty billion, four hundred fifty-two million, thirty-four thousand, fifty-one".
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