Base | Representation |
---|---|
bin | 1110110001100110100111… |
… | …00011110001011110100001 |
3 | 11021001002010111021201212112 |
4 | 13120303103203301132201 |
5 | 13224311404042402332 |
6 | 153034002510205105 |
7 | 6562242250143023 |
oct | 730632343613641 |
9 | 137032114251775 |
10 | 32490681997217 |
11 | a397247a58994 |
12 | 3788ab37b3795 |
13 | 1518b2050bc72 |
14 | 8047b370a013 |
15 | 3b5255844db2 |
hex | 1d8cd38f17a1 |
32490681997217 has 2 divisors, whose sum is σ = 32490681997218. Its totient is φ = 32490681997216.
The previous prime is 32490681997183. The next prime is 32490681997231. The reversal of 32490681997217 is 71279918609423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25924706240161 + 6565975757056 = 5091631^2 + 2562416^2 .
It is a cyclic number.
It is not a de Polignac number, because 32490681997217 - 214 = 32490681980833 is a prime.
It is not a weakly prime, because it can be changed into another prime (32490681997237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16245340998608 + 16245340998609.
It is an arithmetic number, because the mean of its divisors is an integer number (16245340998609).
Almost surely, 232490681997217 is an apocalyptic number.
It is an amenable number.
32490681997217 is a deficient number, since it is larger than the sum of its proper divisors (1).
32490681997217 is an equidigital number, since it uses as much as digits as its factorization.
32490681997217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82301184, while the sum is 68.
The spelling of 32490681997217 in words is "thirty-two trillion, four hundred ninety billion, six hundred eighty-one million, nine hundred ninety-seven thousand, two hundred seventeen".
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