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3249955113 = 31083318371
BaseRepresentation
bin1100000110110110…
…0110000100101001
322101111100211021220
43001231212010221
523123442030423
61254253452253
7143352106536
oct30155460451
98344324256
103249955113
111418573419
127684a1089
133ca40c682
1422b8add8d
151404b99e3
hexc1b66129

3249955113 has 4 divisors (see below), whose sum is σ = 4333273488. Its totient is φ = 2166636740.

The previous prime is 3249955097. The next prime is 3249955117. The reversal of 3249955113 is 3115599423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3249955113 - 24 = 3249955097 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3249955117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541659183 + ... + 541659188.

It is an arithmetic number, because the mean of its divisors is an integer number (1083318372).

Almost surely, 23249955113 is an apocalyptic number.

It is an amenable number.

3249955113 is a deficient number, since it is larger than the sum of its proper divisors (1083318375).

3249955113 is a wasteful number, since it uses less digits than its factorization.

3249955113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1083318374.

The product of its digits is 145800, while the sum is 42.

The square root of 3249955113 is about 57008.3775685644. The cubic root of 3249955113 is about 1481.2412148102.

The spelling of 3249955113 in words is "three billion, two hundred forty-nine million, nine hundred fifty-five thousand, one hundred thirteen".

Divisors: 1 3 1083318371 3249955113