Base | Representation |
---|---|
bin | 1001011101011001011… |
… | …10011100001010011011 |
3 | 1011001221020020011021221 |
4 | 10232230232130022123 |
5 | 20311120210333311 |
6 | 405151243112511 |
7 | 32324210556622 |
oct | 4565456341233 |
9 | 1131836204257 |
10 | 325020402331 |
11 | 1159275a8959 |
12 | 52ba8812737 |
13 | 248596596c1 |
14 | 11a340ba6b9 |
15 | 86c4061671 |
hex | 4bacb9c29b |
325020402331 has 2 divisors, whose sum is σ = 325020402332. Its totient is φ = 325020402330.
The previous prime is 325020402209. The next prime is 325020402347. The reversal of 325020402331 is 133204020523.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 325020402331 - 215 = 325020369563 is a prime.
It is a super-2 number, since 2×3250204023312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 325020402296 and 325020402305.
It is not a weakly prime, because it can be changed into another prime (325020402391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162510201165 + 162510201166.
It is an arithmetic number, because the mean of its divisors is an integer number (162510201166).
Almost surely, 2325020402331 is an apocalyptic number.
325020402331 is a deficient number, since it is larger than the sum of its proper divisors (1).
325020402331 is an equidigital number, since it uses as much as digits as its factorization.
325020402331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 325020402331 its reverse (133204020523), we get a palindrome (458224422854).
The spelling of 325020402331 in words is "three hundred twenty-five billion, twenty million, four hundred two thousand, three hundred thirty-one".
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