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3250504145 = 5799793151
BaseRepresentation
bin1100000110111110…
…1100000111010001
322101112101201102102
43001233230013101
523124112113040
61254313330145
7143356554320
oct30157540721
98345351372
103250504145
111418908969
12768706955
133ca572545
1422b9b40b7
15140577515
hexc1bec1d1

3250504145 has 16 divisors (see below), whose sum is σ = 4462353408. Its totient is φ = 2226657600.

The previous prime is 3250504123. The next prime is 3250504177. The reversal of 3250504145 is 5414050523.

3250504145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3250504145 - 218 = 3250242001 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11681 + ... + 81470.

It is an arithmetic number, because the mean of its divisors is an integer number (278897088).

Almost surely, 23250504145 is an apocalyptic number.

3250504145 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

It is an amenable number.

3250504145 is a deficient number, since it is larger than the sum of its proper divisors (1211849263).

3250504145 is an equidigital number, since it uses as much as digits as its factorization.

3250504145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94160.

The product of its (nonzero) digits is 12000, while the sum is 29.

The square root of 3250504145 is about 57013.1927276486. The cubic root of 3250504145 is about 1481.3246214017.

Adding to 3250504145 its reverse (5414050523), we get a palindrome (8664554668).

The spelling of 3250504145 in words is "three billion, two hundred fifty million, five hundred four thousand, one hundred forty-five".

Divisors: 1 5 7 35 997 4985 6979 34895 93151 465755 652057 3260285 92871547 464357735 650100829 3250504145