Base | Representation |
---|---|
bin | 1001011101100011010… |
… | …01111101001110101100 |
3 | 1011002010222212022011221 |
4 | 10232301221331032230 |
5 | 20311302344110012 |
6 | 405203355553124 |
7 | 32326233603160 |
oct | 4566151751654 |
9 | 1132128768157 |
10 | 325103113132 |
11 | 11596a260796 |
12 | 5301045b7a4 |
13 | 248708288c5 |
14 | 11a4108aca0 |
15 | 86cb44d507 |
hex | 4bb1a7d3ac |
325103113132 has 24 divisors (see below), whose sum is σ = 650504744960. Its totient is φ = 139265937360.
The previous prime is 325103113121. The next prime is 325103113147. The reversal of 325103113132 is 231311301523.
It is a junction number, because it is equal to n+sod(n) for n = 325103113097 and 325103113106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2603244 + ... + 2725267.
Almost surely, 2325103113132 is an apocalyptic number.
It is an amenable number.
325103113132 is an abundant number, since it is smaller than the sum of its proper divisors (325401631828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
325103113132 is a wasteful number, since it uses less digits than its factorization.
325103113132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5330701 (or 5330699 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 325103113132 its reverse (231311301523), we get a palindrome (556414414655).
The spelling of 325103113132 in words is "three hundred twenty-five billion, one hundred three million, one hundred thirteen thousand, one hundred thirty-two".
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