Base | Representation |
---|---|
bin | 101111010100000111110… |
… | …111111011010000110001 |
3 | 102111211111012202201001201 |
4 | 233110013313323100301 |
5 | 411232403110003431 |
6 | 10525403252531201 |
7 | 453623163631051 |
oct | 57240767732061 |
9 | 12454435681051 |
10 | 3251422344241 |
11 | 1043a14170235 |
12 | 446192920b01 |
13 | 1a77b94919b6 |
14 | b3526595561 |
15 | 5989c368461 |
hex | 2f507dfb431 |
3251422344241 has 2 divisors, whose sum is σ = 3251422344242. Its totient is φ = 3251422344240.
The previous prime is 3251422344197. The next prime is 3251422344307. The reversal of 3251422344241 is 1424432241523.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3251155185216 + 267159025 = 1803096^2 + 16345^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3251422344241 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3251422344241.
It is not a weakly prime, because it can be changed into another prime (3251422354241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625711172120 + 1625711172121.
It is an arithmetic number, because the mean of its divisors is an integer number (1625711172121).
Almost surely, 23251422344241 is an apocalyptic number.
It is an amenable number.
3251422344241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3251422344241 is an equidigital number, since it uses as much as digits as its factorization.
3251422344241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 184320, while the sum is 37.
Adding to 3251422344241 its reverse (1424432241523), we get a palindrome (4675854585764).
The spelling of 3251422344241 in words is "three trillion, two hundred fifty-one billion, four hundred twenty-two million, three hundred forty-four thousand, two hundred forty-one".
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