Search a number
-
+
325213164335441 is a prime number
BaseRepresentation
bin100100111110001111001011…
…1001000101111000101010001
31120122111002000120211102201202
41021330132113020233011101
5320111243030032213231
63111400510514240545
7125333606245312634
oct11174362710570521
91518432016742652
10325213164335441
1194694145a83288
12305845a6886155
1310c6061521b875
145a44588a23c1b
15278e819e4e5cb
hex127c79722f151

325213164335441 has 2 divisors, whose sum is σ = 325213164335442. Its totient is φ = 325213164335440.

The previous prime is 325213164335263. The next prime is 325213164335459. The reversal of 325213164335441 is 144533461312523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 312487677737041 + 12725486598400 = 17677321^2 + 3567280^2 .

It is a cyclic number.

It is not a de Polignac number, because 325213164335441 - 230 = 325212090593617 is a prime.

It is not a weakly prime, because it can be changed into another prime (325213164335471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162606582167720 + 162606582167721.

It is an arithmetic number, because the mean of its divisors is an integer number (162606582167721).

Almost surely, 2325213164335441 is an apocalyptic number.

It is an amenable number.

325213164335441 is a deficient number, since it is larger than the sum of its proper divisors (1).

325213164335441 is an equidigital number, since it uses as much as digits as its factorization.

325213164335441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3110400, while the sum is 47.

The spelling of 325213164335441 in words is "three hundred twenty-five trillion, two hundred thirteen billion, one hundred sixty-four million, three hundred thirty-five thousand, four hundred forty-one".