3253121502041 has 4 divisors (see below), whose sum is σ = 3253143420084. Its totient is φ = 3253099584000.

The previous prime is 3253121501989. The next prime is 3253121502047. The reversal of 3253121502041 is 1402051213523.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1741795492441 + 1511326009600 = 1319771^2 + 1229360^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3253121502041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3253121501995 and 3253121502013.

It is not an unprimeable number, because it can be changed into a prime (3253121502047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10734860 + ... + 11033741.

It is an arithmetic number, because the mean of its divisors is an integer number (813285855021).

Almost surely, 2^{3253121502041} is an apocalyptic number.

It is an amenable number.

3253121502041 is a deficient number, since it is larger than the sum of its proper divisors (21918043).

3253121502041 is a wasteful number, since it uses less digits than its factorization.

3253121502041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21918042.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 3253121502041 its reverse (1402051213523), we get a palindrome (4655172715564).

The spelling of 3253121502041 in words is "three trillion, two hundred fifty-three billion, one hundred twenty-one million, five hundred two thousand, forty-one".