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325325013434 = 2162662506717
BaseRepresentation
bin1001011101111101110…
…00011100000110111010
31011002201110102000011122
410232332320130012322
520312231200412214
6405241404025242
732334566662631
oct4567670340672
91132643360148
10325325013434
11115a73541773
1253072832222
13248a77b0265
1411a62730518
1586e0b8188e
hex4bbee1c1ba

325325013434 has 4 divisors (see below), whose sum is σ = 487987520154. Its totient is φ = 162662506716.

The previous prime is 325325013427. The next prime is 325325013439. The reversal of 325325013434 is 434310523523.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 274264832209 + 51060181225 = 523703^2 + 225965^2 .

It is a junction number, because it is equal to n+sod(n) for n = 325325013394 and 325325013403.

It is not an unprimeable number, because it can be changed into a prime (325325013439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81331253357 + ... + 81331253360.

Almost surely, 2325325013434 is an apocalyptic number.

325325013434 is a deficient number, since it is larger than the sum of its proper divisors (162662506720).

325325013434 is a wasteful number, since it uses less digits than its factorization.

325325013434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162662506719.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 325325013434 its reverse (434310523523), we get a palindrome (759635536957).

The spelling of 325325013434 in words is "three hundred twenty-five billion, three hundred twenty-five million, thirteen thousand, four hundred thirty-four".

Divisors: 1 2 162662506717 325325013434