Base | Representation |
---|---|
bin | 100100111111101111101001… |
… | …1010010101101011100101010 |
3 | 1120200012212202110100212212111 |
4 | 1021333133103102231130222 |
5 | 320123141314443411404 |
6 | 3112040011532432534 |
7 | 125354562122444044 |
oct | 11177372322553452 |
9 | 1520185673325774 |
10 | 325420332013354 |
11 | 94763a95804a36 |
12 | 305b878291874a |
13 | 10c7700c4c2076 |
14 | 5a505dca2ca94 |
15 | 2794de27b0104 |
hex | 127f7d34ad72a |
325420332013354 has 4 divisors (see below), whose sum is σ = 488130498020034. Its totient is φ = 162710166006676.
The previous prime is 325420332013333. The next prime is 325420332013391. The reversal of 325420332013354 is 453310233024523.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 325354833384025 + 65498629329 = 18037595^2 + 255927^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81355083003337 + ... + 81355083003340.
Almost surely, 2325420332013354 is an apocalyptic number.
325420332013354 is a deficient number, since it is larger than the sum of its proper divisors (162710166006680).
325420332013354 is a wasteful number, since it uses less digits than its factorization.
325420332013354 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162710166006679.
The product of its (nonzero) digits is 777600, while the sum is 40.
Adding to 325420332013354 its reverse (453310233024523), we get a palindrome (778730565037877).
The spelling of 325420332013354 in words is "three hundred twenty-five trillion, four hundred twenty billion, three hundred thirty-two million, thirteen thousand, three hundred fifty-four".
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