Base | Representation |
---|---|
bin | 101111011000000000001… |
… | …100011110101111001001 |
3 | 102112020020120002102122221 |
4 | 233120000030132233021 |
5 | 411314421122410433 |
6 | 10531332515414041 |
7 | 454131342336211 |
oct | 57300014365711 |
9 | 12466216072587 |
10 | 3255588481993 |
11 | 1045761909191 |
12 | 446b55bb4321 |
13 | 1a8001642773 |
14 | b37dd9d5241 |
15 | 59a42ea972d |
hex | 2f60031ebc9 |
3255588481993 has 4 divisors (see below), whose sum is σ = 3255592256388. Its totient is φ = 3255584707600.
The previous prime is 3255588481987. The next prime is 3255588482011. The reversal of 3255588481993 is 3991848855523.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 1819253347209 + 1436335134784 = 1348797^2 + 1198472^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3255588481993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3255588481913) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113943 + ... + 2554243.
It is an arithmetic number, because the mean of its divisors is an integer number (813898064097).
Almost surely, 23255588481993 is an apocalyptic number.
It is an amenable number.
3255588481993 is a deficient number, since it is larger than the sum of its proper divisors (3774395).
3255588481993 is a wasteful number, since it uses less digits than its factorization.
3255588481993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3774394.
The product of its digits is 373248000, while the sum is 70.
The spelling of 3255588481993 in words is "three trillion, two hundred fifty-five billion, five hundred eighty-eight million, four hundred eighty-one thousand, nine hundred ninety-three".
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