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325625326145443 = 352279243629209
BaseRepresentation
bin100101000001001111000110…
…1111001010000111110100011
31120200221110212211222202200001
41022002132031321100332203
5320140021131443123233
63112314113144240431
7125405440065015652
oct11202361571207643
91520843784882601
10325625326145443
1194832a1a635525
1230630452a70117
1310c9044b396c8c
145a5a4c80c5199
15279a3de3cc27d
hex128278de50fa3

325625326145443 has 4 divisors (see below), whose sum is σ = 325634569809880. Its totient is φ = 325616082481008.

The previous prime is 325625326145423. The next prime is 325625326145477. The reversal of 325625326145443 is 344541623526523.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 325625326145443 - 217 = 325625326014371 is a prime.

It is a super-2 number, since 2×3256253261454432 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (325625326145423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4621779378 + ... + 4621849831.

It is an arithmetic number, because the mean of its divisors is an integer number (81408642452470).

Almost surely, 2325625326145443 is an apocalyptic number.

325625326145443 is a deficient number, since it is larger than the sum of its proper divisors (9243664437).

325625326145443 is an equidigital number, since it uses as much as digits as its factorization.

325625326145443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9243664436.

The product of its digits is 62208000, while the sum is 55.

The spelling of 325625326145443 in words is "three hundred twenty-five trillion, six hundred twenty-five billion, three hundred twenty-six million, one hundred forty-five thousand, four hundred forty-three".

Divisors: 1 35227 9243629209 325625326145443