Search a number
-
+
325655165214433 is a prime number
BaseRepresentation
bin100101000001011101000000…
…0011100010001111011100001
31120201001022220101110112012101
41022002322000130101323201
5320141013234243330213
63112335530111130401
7125410544401640125
oct11202720034217341
91521038811415171
10325655165214433
1194844641a5071a
123063619bb13a01
1310c931c5303912
145a5bb18ddb585
15279b088d17bdd
hex1282e80711ee1

325655165214433 has 2 divisors, whose sum is σ = 325655165214434. Its totient is φ = 325655165214432.

The previous prime is 325655165214373. The next prime is 325655165214521. The reversal of 325655165214433 is 334412561556523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 289999374479424 + 35655790735009 = 17029368^2 + 5971247^2 .

It is a cyclic number.

It is not a de Polignac number, because 325655165214433 - 217 = 325655165083361 is a prime.

It is a super-2 number, since 2×3256551652144332 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (325655165214233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162827582607216 + 162827582607217.

It is an arithmetic number, because the mean of its divisors is an integer number (162827582607217).

Almost surely, 2325655165214433 is an apocalyptic number.

It is an amenable number.

325655165214433 is a deficient number, since it is larger than the sum of its proper divisors (1).

325655165214433 is an equidigital number, since it uses as much as digits as its factorization.

325655165214433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38880000, while the sum is 55.

The spelling of 325655165214433 in words is "three hundred twenty-five trillion, six hundred fifty-five billion, one hundred sixty-five million, two hundred fourteen thousand, four hundred thirty-three".