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326055365521401 = 3472312449400861
BaseRepresentation
bin100101000100010111010111…
…0001111010010111111111001
31120202110120220000221112200210
41022020232232033102333321
5320214042342033141101
63113243433404421333
7125451502625264355
oct11210565617227771
91522416800845623
10326055365521401
119498933865566a
123069b86a247849
1310cc1b732a5b99
145a73241a22465
1527a66ad0cb7d6
hex1288bae3d2ff9

326055365521401 has 8 divisors (see below), whose sum is σ = 443990284965504. Its totient is φ = 212745344879120.

The previous prime is 326055365521399. The next prime is 326055365521463. The reversal of 326055365521401 is 104125563550623.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 326055365521401 - 21 = 326055365521399 is a prime.

It is a super-3 number, since 3×3260553655214013 (a number of 45 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (326055365321401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1156224700290 + ... + 1156224700571.

It is an arithmetic number, because the mean of its divisors is an integer number (55498785620688).

Almost surely, 2326055365521401 is an apocalyptic number.

It is an amenable number.

326055365521401 is a deficient number, since it is larger than the sum of its proper divisors (117934919444103).

326055365521401 is a wasteful number, since it uses less digits than its factorization.

326055365521401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2312449400911.

The product of its (nonzero) digits is 3240000, while the sum is 48.

The spelling of 326055365521401 in words is "three hundred twenty-six trillion, fifty-five billion, three hundred sixty-five million, five hundred twenty-one thousand, four hundred one".

Divisors: 1 3 47 141 2312449400861 6937348202583 108685121840467 326055365521401