Base | Representation |
---|---|
bin | 100101100001010110111001… |
… | …0111100100011000100100001 |
3 | 1121021120112012001121210201121 |
4 | 1023002231302330203010201 |
5 | 321224334111200321231 |
6 | 3125534155022132241 |
7 | 126342416234023543 |
oct | 11302556274430441 |
9 | 1537515161553647 |
10 | 330040100401441 |
11 | 96185247604711 |
12 | 31023b95a21081 |
13 | 1122085664aa51 |
14 | 5b70051847693 |
15 | 2825178d53311 |
hex | 12c2b72f23121 |
330040100401441 has 2 divisors, whose sum is σ = 330040100401442. Its totient is φ = 330040100401440.
The previous prime is 330040100401409. The next prime is 330040100401447. The reversal of 330040100401441 is 144104001040033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 289309346737216 + 40730753664225 = 17009096^2 + 6382065^2 .
It is a cyclic number.
It is not a de Polignac number, because 330040100401441 - 25 = 330040100401409 is a prime.
It is not a weakly prime, because it can be changed into another prime (330040100401447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165020050200720 + 165020050200721.
It is an arithmetic number, because the mean of its divisors is an integer number (165020050200721).
Almost surely, 2330040100401441 is an apocalyptic number.
It is an amenable number.
330040100401441 is a deficient number, since it is larger than the sum of its proper divisors (1).
330040100401441 is an equidigital number, since it uses as much as digits as its factorization.
330040100401441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 330040100401441 its reverse (144104001040033), we get a palindrome (474144101441474).
The spelling of 330040100401441 in words is "three hundred thirty trillion, forty billion, one hundred million, four hundred one thousand, four hundred forty-one".
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