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330040100401441 is a prime number
BaseRepresentation
bin100101100001010110111001…
…0111100100011000100100001
31121021120112012001121210201121
41023002231302330203010201
5321224334111200321231
63125534155022132241
7126342416234023543
oct11302556274430441
91537515161553647
10330040100401441
1196185247604711
1231023b95a21081
131122085664aa51
145b70051847693
152825178d53311
hex12c2b72f23121

330040100401441 has 2 divisors, whose sum is σ = 330040100401442. Its totient is φ = 330040100401440.

The previous prime is 330040100401409. The next prime is 330040100401447. The reversal of 330040100401441 is 144104001040033.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 289309346737216 + 40730753664225 = 17009096^2 + 6382065^2 .

It is a cyclic number.

It is not a de Polignac number, because 330040100401441 - 25 = 330040100401409 is a prime.

It is not a weakly prime, because it can be changed into another prime (330040100401447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165020050200720 + 165020050200721.

It is an arithmetic number, because the mean of its divisors is an integer number (165020050200721).

Almost surely, 2330040100401441 is an apocalyptic number.

It is an amenable number.

330040100401441 is a deficient number, since it is larger than the sum of its proper divisors (1).

330040100401441 is an equidigital number, since it uses as much as digits as its factorization.

330040100401441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 330040100401441 its reverse (144104001040033), we get a palindrome (474144101441474).

The spelling of 330040100401441 in words is "three hundred thirty trillion, forty billion, one hundred million, four hundred one thousand, four hundred forty-one".