330044132413442 has 4 divisors (see below), whose sum is σ = 495066198620166. Its totient is φ = 165022066206720.

The previous prime is 330044132413439. The next prime is 330044132413493. The reversal of 330044132413442 is 244314231440033.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 295296420324481 + 34747712088961 = 17184191^2 + 5894719^2 .

It is a junction number, because it is equal to n+sod(n) for n = 330044132413396 and 330044132413405.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82511033103359 + ... + 82511033103362.

Almost surely, 2^{330044132413442} is an apocalyptic number.

330044132413442 is a deficient number, since it is larger than the sum of its proper divisors (165022066206724).

330044132413442 is a wasteful number, since it uses less digits than its factorization.

330044132413442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 165022066206723.

The product of its (nonzero) digits is 331776, while the sum is 38.

Adding to 330044132413442 its reverse (244314231440033), we get a palindrome (574358363853475).

The spelling of 330044132413442 in words is "three hundred thirty trillion, forty-four billion, one hundred thirty-two million, four hundred thirteen thousand, four hundred forty-two".