Base | Representation |
---|---|
bin | 110000000010100100111… |
… | …000101100110100100001 |
3 | 102200121020100122122022001 |
4 | 300002210320230310201 |
5 | 413042031102213101 |
6 | 11004332530044001 |
7 | 460340215200655 |
oct | 60024470546441 |
9 | 12617210578261 |
10 | 3301301210401 |
11 | 106308a517677 |
12 | 453993119601 |
13 | 1ac4080cb69c |
14 | b5ad8b92a65 |
15 | 5ad1b281901 |
hex | 300a4e2cd21 |
3301301210401 has 2 divisors, whose sum is σ = 3301301210402. Its totient is φ = 3301301210400.
The previous prime is 3301301210393. The next prime is 3301301210413. The reversal of 3301301210401 is 1040121031033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2923156156176 + 378145054225 = 1709724^2 + 614935^2 .
It is a cyclic number.
It is not a de Polignac number, because 3301301210401 - 23 = 3301301210393 is a prime.
It is a super-3 number, since 3×33013012104013 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3301301210461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650650605200 + 1650650605201.
It is an arithmetic number, because the mean of its divisors is an integer number (1650650605201).
Almost surely, 23301301210401 is an apocalyptic number.
It is an amenable number.
3301301210401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3301301210401 is an equidigital number, since it uses as much as digits as its factorization.
3301301210401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3301301210401 its reverse (1040121031033), we get a palindrome (4341422241434).
The spelling of 3301301210401 in words is "three trillion, three hundred one billion, three hundred one million, two hundred ten thousand, four hundred one".
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