Base | Representation |
---|---|
bin | 110000000010101011100… |
… | …111011111110001101010 |
3 | 102200121112020011010000002 |
4 | 300002223213133301222 |
5 | 413042244010003114 |
6 | 11004352042343002 |
7 | 460343056116542 |
oct | 60025347376152 |
9 | 12617466133002 |
10 | 3301414141034 |
11 | 1063138240079 |
12 | 453a04abaa62 |
13 | 1ac42561b949 |
14 | b5b09b8c322 |
15 | 5ad2613c7de |
hex | 300ab9dfc6a |
3301414141034 has 4 divisors (see below), whose sum is σ = 4952121211554. Its totient is φ = 1650707070516.
The previous prime is 3301414141027. The next prime is 3301414141037. The reversal of 3301414141034 is 4301414141033.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3026392560409 + 275021580625 = 1739653^2 + 524425^2 .
It is a junction number, because it is equal to n+sod(n) for n = 3301414140988 and 3301414141006.
It is not an unprimeable number, because it can be changed into a prime (3301414141037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 825353535257 + ... + 825353535260.
Almost surely, 23301414141034 is an apocalyptic number.
3301414141034 is a deficient number, since it is larger than the sum of its proper divisors (1650707070520).
3301414141034 is a wasteful number, since it uses less digits than its factorization.
3301414141034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1650707070519.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 3301414141034 its reverse (4301414141033), we get a palindrome (7602828282067).
Subtracting 3301414141034 from its reverse (4301414141033), we obtain a palindrome (999999999999).
The spelling of 3301414141034 in words is "three trillion, three hundred one billion, four hundred fourteen million, one hundred forty-one thousand, thirty-four".
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