Base | Representation |
---|---|
bin | 110000000010101100001… |
… | …110110010111101101001 |
3 | 102200121112221112111222022 |
4 | 300002230032302331221 |
5 | 413042304124140431 |
6 | 11004353051234225 |
7 | 460343242515251 |
oct | 60025416627551 |
9 | 12617487474868 |
10 | 3301424443241 |
11 | 10631430372a1 |
12 | 453a08448975 |
13 | 1ac4277b7c22 |
14 | b5b0b2b0961 |
15 | 5ad26ec507b |
hex | 300ac3b2f69 |
3301424443241 has 2 divisors, whose sum is σ = 3301424443242. Its totient is φ = 3301424443240.
The previous prime is 3301424443223. The next prime is 3301424443253. The reversal of 3301424443241 is 1423444241033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2061007655641 + 1240416787600 = 1435621^2 + 1113740^2 .
It is a cyclic number.
It is not a de Polignac number, because 3301424443241 - 214 = 3301424426857 is a prime.
It is not a weakly prime, because it can be changed into another prime (3301424443201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650712221620 + 1650712221621.
It is an arithmetic number, because the mean of its divisors is an integer number (1650712221621).
Almost surely, 23301424443241 is an apocalyptic number.
It is an amenable number.
3301424443241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3301424443241 is an equidigital number, since it uses as much as digits as its factorization.
3301424443241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 3301424443241 its reverse (1423444241033), we get a palindrome (4724868684274).
The spelling of 3301424443241 in words is "three trillion, three hundred one billion, four hundred twenty-four million, four hundred forty-three thousand, two hundred forty-one".
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