Base | Representation |
---|---|
bin | 110000000100001010001… |
… | …010100111000001010101 |
3 | 102200202121202222121210021 |
4 | 300010022022213001111 |
5 | 413104021100412203 |
6 | 11005213305425141 |
7 | 460430300124220 |
oct | 60041212470125 |
9 | 12622552877707 |
10 | 3303000404053 |
11 | 1063881689a49 |
12 | 45418819b1b1 |
13 | 1ac619154c0c |
14 | b5c1a7085b7 |
15 | 5adba5265bd |
hex | 3010a2a7055 |
3303000404053 has 32 divisors (see below), whose sum is σ = 3952645320960. Its totient is φ = 2700192983040.
The previous prime is 3303000404017. The next prime is 3303000404057. The reversal of 3303000404053 is 3504040003033.
It is not a de Polignac number, because 3303000404053 - 233 = 3294410469461 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3303000404057) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 201185701 + ... + 201202117.
It is an arithmetic number, because the mean of its divisors is an integer number (123520166280).
Almost surely, 23303000404053 is an apocalyptic number.
It is an amenable number.
3303000404053 is a deficient number, since it is larger than the sum of its proper divisors (649644916907).
3303000404053 is a wasteful number, since it uses less digits than its factorization.
3303000404053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28477.
The product of its (nonzero) digits is 6480, while the sum is 25.
Adding to 3303000404053 its reverse (3504040003033), we get a palindrome (6807040407086).
The spelling of 3303000404053 in words is "three trillion, three hundred three billion, four hundred four thousand, fifty-three".
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