Base | Representation |
---|---|
bin | 100101100011011110111011… |
… | …0001010010010111001101001 |
3 | 1121022121110011211100021000121 |
4 | 1023012331312022102321221 |
5 | 321244130332300104001 |
6 | 3130320305010003241 |
7 | 126402500105426560 |
oct | 11306756612227151 |
9 | 1538543154307017 |
10 | 330332212113001 |
11 | 96288116aa406a |
12 | 31070719576521 |
13 | 1124226a11a957 |
14 | 5b80243080bd7 |
15 | 282ca73c316a1 |
hex | 12c6f76292e69 |
330332212113001 has 4 divisors (see below), whose sum is σ = 377522528129152. Its totient is φ = 283141896096852.
The previous prime is 330332212112971. The next prime is 330332212113061. The reversal of 330332212113001 is 100311212233033.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 330332212113001 - 219 = 330332211588713 is a prime.
It is not an unprimeable number, because it can be changed into a prime (330332212113061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23595158008065 + ... + 23595158008078.
It is an arithmetic number, because the mean of its divisors is an integer number (94380632032288).
Almost surely, 2330332212113001 is an apocalyptic number.
It is an amenable number.
330332212113001 is a deficient number, since it is larger than the sum of its proper divisors (47190316016151).
330332212113001 is an equidigital number, since it uses as much as digits as its factorization.
330332212113001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47190316016150.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 330332212113001 its reverse (100311212233033), we get a palindrome (430643424346034).
The spelling of 330332212113001 in words is "three hundred thirty trillion, three hundred thirty-two billion, two hundred twelve million, one hundred thirteen thousand, one".
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