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33040221112433 is a prime number
BaseRepresentation
bin1111000001100110001101…
…01001001000100001110001
311022222121120211002020200002
413200303012221020201301
513312312333101044213
6154134245032435345
76650035323432623
oct740630651104161
9138877524066602
1033040221112433
11a589308508917
1238574bb248b55
1315588aaa8b562
14823225d6ac13
153c46ba62e658
hex1e0cc6a48871

33040221112433 has 2 divisors, whose sum is σ = 33040221112434. Its totient is φ = 33040221112432.

The previous prime is 33040221112417. The next prime is 33040221112441. The reversal of 33040221112433 is 33421112204033.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32233642891024 + 806578221409 = 5677468^2 + 898097^2 .

It is an emirp because it is prime and its reverse (33421112204033) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33040221112433 - 24 = 33040221112417 is a prime.

It is a super-2 number, since 2×330402211124332 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33040221112396 and 33040221112405.

It is not a weakly prime, because it can be changed into another prime (33040221112333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16520110556216 + 16520110556217.

It is an arithmetic number, because the mean of its divisors is an integer number (16520110556217).

Almost surely, 233040221112433 is an apocalyptic number.

It is an amenable number.

33040221112433 is a deficient number, since it is larger than the sum of its proper divisors (1).

33040221112433 is an equidigital number, since it uses as much as digits as its factorization.

33040221112433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 33040221112433 its reverse (33421112204033), we get a palindrome (66461333316466).

The spelling of 33040221112433 in words is "thirty-three trillion, forty billion, two hundred twenty-one million, one hundred twelve thousand, four hundred thirty-three".