Base | Representation |
---|---|
bin | 1111000001101011110000… |
… | …01101011100110101001011 |
3 | 11022222220021102202120120001 |
4 | 13200311320031130311023 |
5 | 13312334433222400021 |
6 | 154135500412543431 |
7 | 6650202206316301 |
oct | 740657015346513 |
9 | 138886242676501 |
10 | 33043200200011 |
11 | a58a5a7095471 |
12 | 3857bb0a81b77 |
13 | 1558c64030281 |
14 | 82342988c271 |
15 | 3c47e1e42091 |
hex | 1e0d7835cd4b |
33043200200011 has 2 divisors, whose sum is σ = 33043200200012. Its totient is φ = 33043200200010.
The previous prime is 33043200199967. The next prime is 33043200200041. The reversal of 33043200200011 is 11000200234033.
It is a strong prime.
It is an emirp because it is prime and its reverse (11000200234033) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33043200200011 - 211 = 33043200197963 is a prime.
It is not a weakly prime, because it can be changed into another prime (33043200200041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16521600100005 + 16521600100006.
It is an arithmetic number, because the mean of its divisors is an integer number (16521600100006).
Almost surely, 233043200200011 is an apocalyptic number.
33043200200011 is a deficient number, since it is larger than the sum of its proper divisors (1).
33043200200011 is an equidigital number, since it uses as much as digits as its factorization.
33043200200011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 33043200200011 its reverse (11000200234033), we get a palindrome (44043400434044).
The spelling of 33043200200011 in words is "thirty-three trillion, forty-three billion, two hundred million, two hundred thousand, eleven".
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