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33044002041 = 322034999849
BaseRepresentation
bin11110110001100100…
…110111010011111001
310011021220010020011110
4132301210313103321
51020133231031131
623102531350533
72246601245241
oct366144672371
9104256106143
1033044002041
11130175288a6
1264a2452449
133167c1493b
141856826b21
15cd5eb0646
hex7b19374f9

33044002041 has 8 divisors (see below), whose sum is σ = 44078677600. Its totient is φ = 22019330592.

The previous prime is 33044002039. The next prime is 33044002049. The reversal of 33044002041 is 14020044033.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 33044002041 - 21 = 33044002039 is a prime.

It is a super-2 number, since 2×330440020412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33044001999 and 33044002017.

It is not an unprimeable number, because it can be changed into a prime (33044002049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2493316 + ... + 2506533.

It is an arithmetic number, because the mean of its divisors is an integer number (5509834700).

Almost surely, 233044002041 is an apocalyptic number.

It is an amenable number.

33044002041 is a deficient number, since it is larger than the sum of its proper divisors (11034675559).

33044002041 is a wasteful number, since it uses less digits than its factorization.

33044002041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5002055.

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 33044002041 its reverse (14020044033), we get a palindrome (47064046074).

The spelling of 33044002041 in words is "thirty-three billion, forty-four million, two thousand, forty-one".

Divisors: 1 3 2203 6609 4999849 14999547 11014667347 33044002041