Base | Representation |
---|---|
bin | 110000000101011110001… |
… | …100010101010100110011 |
3 | 102200220021000122201200221 |
4 | 300011132030111110303 |
5 | 413114412444021003 |
6 | 11010005225153511 |
7 | 460510235525335 |
oct | 60053614252463 |
9 | 12626230581627 |
10 | 3304410142003 |
11 | 1064435419a33 |
12 | 45450032b897 |
13 | 1ac7b2232b99 |
14 | b5d11a33455 |
15 | 5ae4e1917bd |
hex | 3015e315533 |
3304410142003 has 4 divisors (see below), whose sum is σ = 3304495081368. Its totient is φ = 3304325202640.
The previous prime is 3304410141931. The next prime is 3304410142039. The reversal of 3304410142003 is 3002410144033.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3304410142003 - 29 = 3304410141491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3304410172003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42411301 + ... + 42489142.
It is an arithmetic number, because the mean of its divisors is an integer number (826123770342).
Almost surely, 23304410142003 is an apocalyptic number.
3304410142003 is a deficient number, since it is larger than the sum of its proper divisors (84939365).
3304410142003 is an equidigital number, since it uses as much as digits as its factorization.
3304410142003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84939364.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 3304410142003 its reverse (3002410144033), we get a palindrome (6306820286036).
The spelling of 3304410142003 in words is "three trillion, three hundred four billion, four hundred ten million, one hundred forty-two thousand, three".
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