Base | Representation |
---|---|
bin | 100101101000010110100000… |
… | …0111011110011011101011011 |
3 | 1121101222102022002021000010212 |
4 | 1023100231000323303131123 |
5 | 321341111213002114211 |
6 | 3131551525202401335 |
7 | 126502025423666261 |
oct | 11320550073633533 |
9 | 1541872262230125 |
10 | 331001334019931 |
11 | 9651597195a383 |
12 | 3115a33906024b |
13 | 112903a42c94b3 |
14 | 5ba479b484431 |
15 | 284018705e38b |
hex | 12d0b40ef375b |
331001334019931 has 2 divisors, whose sum is σ = 331001334019932. Its totient is φ = 331001334019930.
The previous prime is 331001334019919. The next prime is 331001334019987. The reversal of 331001334019931 is 139910433100133.
It is a weak prime.
It is an emirp because it is prime and its reverse (139910433100133) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331001334019931 is a prime.
It is a super-2 number, since 2×3310013340199312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (331001334019331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165500667009965 + 165500667009966.
It is an arithmetic number, because the mean of its divisors is an integer number (165500667009966).
Almost surely, 2331001334019931 is an apocalyptic number.
331001334019931 is a deficient number, since it is larger than the sum of its proper divisors (1).
331001334019931 is an equidigital number, since it uses as much as digits as its factorization.
331001334019931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 41.
The spelling of 331001334019931 in words is "three hundred thirty-one trillion, one billion, three hundred thirty-four million, nineteen thousand, nine hundred thirty-one".
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