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33100145017 is a prime number
BaseRepresentation
bin11110110100111011…
…000010000101111001
310011102210202120211221
4132310323002011321
51020242114120032
623112254552041
72251152406342
oct366473020571
9104383676757
1033100145017
1113046194955
1264b9208621
133176741134
14186007d0c9
15cdada0597
hex7b4ec2179

33100145017 has 2 divisors, whose sum is σ = 33100145018. Its totient is φ = 33100145016.

The previous prime is 33100145011. The next prime is 33100145027. The reversal of 33100145017 is 71054100133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22469710201 + 10630434816 = 149899^2 + 103104^2 .

It is a cyclic number.

It is not a de Polignac number, because 33100145017 - 23 = 33100145009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 33100144982 and 33100145000.

It is not a weakly prime, because it can be changed into another prime (33100145011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16550072508 + 16550072509.

It is an arithmetic number, because the mean of its divisors is an integer number (16550072509).

Almost surely, 233100145017 is an apocalyptic number.

It is an amenable number.

33100145017 is a deficient number, since it is larger than the sum of its proper divisors (1).

33100145017 is an equidigital number, since it uses as much as digits as its factorization.

33100145017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

The spelling of 33100145017 in words is "thirty-three billion, one hundred million, one hundred forty-five thousand, seventeen".