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33101002113 = 317123644377
BaseRepresentation
bin11110110100111110…
…010011010110000001
310011102212101010120020
4132310332103112001
51020242324031423
623112325204053
72251162606224
oct366476232601
9104385333506
1033101002113
111304671a8a3
1264b9560629
1331769812aa
1418602235bb
15cdaebe4e3
hex7b4f93581

33101002113 has 8 divisors (see below), whose sum is σ = 44137315488. Its totient is φ = 22066011744.

The previous prime is 33101002111. The next prime is 33101002117. The reversal of 33101002113 is 31120010133.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 33101002113 - 21 = 33101002111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 33101002092 and 33101002101.

It is not an unprimeable number, because it can be changed into a prime (33101002111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 270820 + ... + 373557.

It is an arithmetic number, because the mean of its divisors is an integer number (5517164436).

Almost surely, 233101002113 is an apocalyptic number.

It is an amenable number.

33101002113 is a deficient number, since it is larger than the sum of its proper divisors (11036313375).

33101002113 is a wasteful number, since it uses less digits than its factorization.

33101002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 661503.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 33101002113 its reverse (31120010133), we get a palindrome (64221012246).

The spelling of 33101002113 in words is "thirty-three billion, one hundred one million, two thousand, one hundred thirteen".

Divisors: 1 3 17123 51369 644377 1933131 11033667371 33101002113