33102203120113 has 4 divisors (see below), whose sum is σ = 33102408017008. Its totient is φ = 33101998223220.

The previous prime is 33102203120111. The next prime is 33102203120117. The reversal of 33102203120113 is 31102130220133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 33102203120113 - 2¹ = 33102203120111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33102203120111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102205923 + ... + 102529288.

It is an arithmetic number, because the mean of its divisors is an integer number (8275602004252).

Almost surely, 2^{33102203120113} is an apocalyptic number.

It is an amenable number.

33102203120113 is a deficient number, since it is larger than the sum of its proper divisors (204896895).

33102203120113 is a wasteful number, since it uses less digits than its factorization.

33102203120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204896894.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 33102203120113 its reverse (31102130220133), we get a palindrome (64204333340246).

The spelling of 33102203120113 in words is "thirty-three trillion, one hundred two billion, two hundred three million, one hundred twenty thousand, one hundred thirteen".