Base | Representation |
---|---|
bin | 100101101001001110010100… |
… | …1100101001110101001001011 |
3 | 1121102101212200211201021020011 |
4 | 1023102130221211032221023 |
5 | 321400042210013412113 |
6 | 3132122551354412351 |
7 | 126513501022104136 |
oct | 11322345145165113 |
9 | 1542355624637204 |
10 | 331121201310283 |
11 | 965617929117aa |
12 | 311796104310b7 |
13 | 1129b797b59937 |
14 | 5baa4ccd2321d |
15 | 284335054d63d |
hex | 12d272994ea4b |
331121201310283 has 2 divisors, whose sum is σ = 331121201310284. Its totient is φ = 331121201310282.
The previous prime is 331121201310139. The next prime is 331121201310323. The reversal of 331121201310283 is 382013102121133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331121201310283 - 217 = 331121201179211 is a prime.
It is not a weakly prime, because it can be changed into another prime (331121201310583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165560600655141 + 165560600655142.
It is an arithmetic number, because the mean of its divisors is an integer number (165560600655142).
Almost surely, 2331121201310283 is an apocalyptic number.
331121201310283 is a deficient number, since it is larger than the sum of its proper divisors (1).
331121201310283 is an equidigital number, since it uses as much as digits as its factorization.
331121201310283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 331121201310283 in words is "three hundred thirty-one trillion, one hundred twenty-one billion, two hundred one million, three hundred ten thousand, two hundred eighty-three".
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