Base | Representation |
---|---|
bin | 100101101001001110010100… |
… | …1100101001111110111111011 |
3 | 1121102101212200211201112010211 |
4 | 1023102130221211033313323 |
5 | 321400042210014042243 |
6 | 3132122551354451551 |
7 | 126513501022124626 |
oct | 11322345145176773 |
9 | 1542355624645124 |
10 | 331121201315323 |
11 | 96561792915571 |
12 | 31179610433bb7 |
13 | 1129b797b5c013 |
14 | 5baa4ccd24dbd |
15 | 284335054ed9d |
hex | 12d272994fdfb |
331121201315323 has 2 divisors, whose sum is σ = 331121201315324. Its totient is φ = 331121201315322.
The previous prime is 331121201315269. The next prime is 331121201315357. The reversal of 331121201315323 is 323513102121133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331121201315323 - 29 = 331121201314811 is a prime.
It is not a weakly prime, because it can be changed into another prime (331121201310323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165560600657661 + 165560600657662.
It is an arithmetic number, because the mean of its divisors is an integer number (165560600657662).
Almost surely, 2331121201315323 is an apocalyptic number.
331121201315323 is a deficient number, since it is larger than the sum of its proper divisors (1).
331121201315323 is an equidigital number, since it uses as much as digits as its factorization.
331121201315323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 331121201315323 its reverse (323513102121133), we get a palindrome (654634303436456).
The spelling of 331121201315323 in words is "three hundred thirty-one trillion, one hundred twenty-one billion, two hundred one million, three hundred fifteen thousand, three hundred twenty-three".
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