Base | Representation |
---|---|
bin | 100101101001010010011011… |
… | …0110000001001100010000011 |
3 | 1121102102201102212222102020121 |
4 | 1023102210312300021202003 |
5 | 321400213231111230311 |
6 | 3132131005542521111 |
7 | 126514232250402244 |
oct | 11322446660114203 |
9 | 1542381385872217 |
10 | 331130012211331 |
11 | 965654a4396103 |
12 | 3117b26b136197 |
13 | 1129c57039b658 |
14 | 5baaac7192ccb |
15 | 28436b8d25b71 |
hex | 12d2936c09883 |
331130012211331 has 2 divisors, whose sum is σ = 331130012211332. Its totient is φ = 331130012211330.
The previous prime is 331130012211287. The next prime is 331130012211377. The reversal of 331130012211331 is 133112210031133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331130012211331 - 213 = 331130012203139 is a prime.
It is a super-2 number, since 2×3311300122113312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 331130012211296 and 331130012211305.
It is not a weakly prime, because it can be changed into another prime (331130012221331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565006105665 + 165565006105666.
It is an arithmetic number, because the mean of its divisors is an integer number (165565006105666).
Almost surely, 2331130012211331 is an apocalyptic number.
331130012211331 is a deficient number, since it is larger than the sum of its proper divisors (1).
331130012211331 is an equidigital number, since it uses as much as digits as its factorization.
331130012211331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 331130012211331 its reverse (133112210031133), we get a palindrome (464242222242464).
The spelling of 331130012211331 in words is "three hundred thirty-one trillion, one hundred thirty billion, twelve million, two hundred eleven thousand, three hundred thirty-one".
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