Base | Representation |
---|---|
bin | 110000001011111000110… |
… | …111110111100110001011 |
3 | 102201120001012112121102111 |
4 | 300023320313313212023 |
5 | 413223020323310011 |
6 | 11013105035243151 |
7 | 461143051260301 |
oct | 60137067674613 |
9 | 12646035477374 |
10 | 3311300213131 |
11 | 1067350710399 |
12 | 4559038a94b7 |
13 | 1b033c829c51 |
14 | b63a6b36271 |
15 | 5b203ee4121 |
hex | 302f8df798b |
3311300213131 has 4 divisors (see below), whose sum is σ = 3311315865000. Its totient is φ = 3311284561264.
The previous prime is 3311300213113. The next prime is 3311300213171. The reversal of 3311300213131 is 1313120031133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3311300213131 - 27 = 3311300213003 is a prime.
It is a super-2 number, since 2×33113002131312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3311300213171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7504186 + ... + 7933183.
It is an arithmetic number, because the mean of its divisors is an integer number (827828966250).
Almost surely, 23311300213131 is an apocalyptic number.
3311300213131 is a deficient number, since it is larger than the sum of its proper divisors (15651869).
3311300213131 is a wasteful number, since it uses less digits than its factorization.
3311300213131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15651868.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 3311300213131 its reverse (1313120031133), we get a palindrome (4624420244264).
The spelling of 3311300213131 in words is "three trillion, three hundred eleven billion, three hundred million, two hundred thirteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •