Base | Representation |
---|---|
bin | 110000001011111000111… |
… | …100000110001000011001 |
3 | 102201120001021121220110121 |
4 | 300023320330012020121 |
5 | 413223021114234431 |
6 | 11013105115113241 |
7 | 461143063554034 |
oct | 60137074061031 |
9 | 12646037556417 |
10 | 3311301321241 |
11 | 10673512a7991 |
12 | 455904142821 |
13 | 1b033cb27434 |
14 | b63a6d4401b |
15 | 5b204162611 |
hex | 302f8f06219 |
3311301321241 has 2 divisors, whose sum is σ = 3311301321242. Its totient is φ = 3311301321240.
The previous prime is 3311301321151. The next prime is 3311301321287. The reversal of 3311301321241 is 1421231031133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3004380889225 + 306920432016 = 1733315^2 + 554004^2 .
It is a cyclic number.
It is not a de Polignac number, because 3311301321241 - 29 = 3311301320729 is a prime.
It is not a weakly prime, because it can be changed into another prime (3311301361241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655650660620 + 1655650660621.
It is an arithmetic number, because the mean of its divisors is an integer number (1655650660621).
Almost surely, 23311301321241 is an apocalyptic number.
It is an amenable number.
3311301321241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311301321241 is an equidigital number, since it uses as much as digits as its factorization.
3311301321241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 3311301321241 its reverse (1421231031133), we get a palindrome (4732532352374).
The spelling of 3311301321241 in words is "three trillion, three hundred eleven billion, three hundred one million, three hundred twenty-one thousand, two hundred forty-one".
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