Base | Representation |
---|---|
bin | 1001101000110001110… |
… | …01111001100101011001 |
3 | 1011122201001002210010111 |
4 | 10310120321321211121 |
5 | 20411123330004144 |
6 | 412041423444321 |
7 | 32631501135454 |
oct | 4643071714531 |
9 | 1148631083114 |
10 | 331130313049 |
11 | 11848247a248 |
12 | 54212a566a1 |
13 | 252c1428ca3 |
14 | 1205373a49b |
15 | 893065a534 |
hex | 4d18e79959 |
331130313049 has 2 divisors, whose sum is σ = 331130313050. Its totient is φ = 331130313048.
The previous prime is 331130312963. The next prime is 331130313133. The reversal of 331130313049 is 940313031133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 168721313049 + 162409000000 = 410757^2 + 403000^2 .
It is a cyclic number.
It is not a de Polignac number, because 331130313049 - 215 = 331130280281 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 331130313049.
It is not a weakly prime, because it can be changed into another prime (331130313149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565156524 + 165565156525.
It is an arithmetic number, because the mean of its divisors is an integer number (165565156525).
Almost surely, 2331130313049 is an apocalyptic number.
It is an amenable number.
331130313049 is a deficient number, since it is larger than the sum of its proper divisors (1).
331130313049 is an equidigital number, since it uses as much as digits as its factorization.
331130313049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
The spelling of 331130313049 in words is "three hundred thirty-one billion, one hundred thirty million, three hundred thirteen thousand, forty-nine".
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