Base | Representation |
---|---|
bin | 100101101001010011000001… |
… | …1100001011011111001001011 |
3 | 1121102102211202122120000120001 |
4 | 1023102212003201123321023 |
5 | 321400223400322400021 |
6 | 3132131341432543431 |
7 | 126514306210205263 |
oct | 11322460341337113 |
9 | 1542384678500501 |
10 | 331131300200011 |
11 | 96565aa542a063 |
12 | 3117b56a551b77 |
13 | 1129c71718c42c |
14 | 5baabaa2687a3 |
15 | 2843741e42091 |
hex | 12d298385be4b |
331131300200011 has 4 divisors (see below), whose sum is σ = 331131400152624. Its totient is φ = 331131200247400.
The previous prime is 331131300199927. The next prime is 331131300200023. The reversal of 331131300200011 is 110002003131133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 331131300200011 - 211 = 331131300197963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (331131300201011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44830360 + ... + 51691621.
It is an arithmetic number, because the mean of its divisors is an integer number (82782850038156).
Almost surely, 2331131300200011 is an apocalyptic number.
331131300200011 is a deficient number, since it is larger than the sum of its proper divisors (99952613).
331131300200011 is an equidigital number, since it uses as much as digits as its factorization.
331131300200011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99952612.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 331131300200011 its reverse (110002003131133), we get a palindrome (441133303331144).
The spelling of 331131300200011 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, three hundred million, two hundred thousand, eleven".
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