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331140142014001 is a prime number
BaseRepresentation
bin100101101001010111001001…
…0100010010001111000110001
31121102110200120211222201011021
41023102232102202101320301
5321400400002323422001
63132135403043415441
7126515041262323525
oct11322562242217061
91542420524881137
10331140142014001
11965698223a7851
1231181217684581
13112a04c5c35828
145bab3a8663d85
152843aad2c3ba1
hex12d2b92891e31

331140142014001 has 2 divisors, whose sum is σ = 331140142014002. Its totient is φ = 331140142014000.

The previous prime is 331140142013963. The next prime is 331140142014047. The reversal of 331140142014001 is 100410241041133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 331083498490000 + 56643524001 = 18195700^2 + 237999^2 .

It is a cyclic number.

It is not a de Polignac number, because 331140142014001 - 211 = 331140142011953 is a prime.

It is not a weakly prime, because it can be changed into another prime (331140142014601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165570071007000 + 165570071007001.

It is an arithmetic number, because the mean of its divisors is an integer number (165570071007001).

Almost surely, 2331140142014001 is an apocalyptic number.

It is an amenable number.

331140142014001 is a deficient number, since it is larger than the sum of its proper divisors (1).

331140142014001 is an equidigital number, since it uses as much as digits as its factorization.

331140142014001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 331140142014001 its reverse (100410241041133), we get a palindrome (431550383055134).

The spelling of 331140142014001 in words is "three hundred thirty-one trillion, one hundred forty billion, one hundred forty-two million, fourteen thousand, one".