Base | Representation |
---|---|
bin | 1111000011110000000101… |
… | …00110001100101100000010 |
3 | 11100020200122102100110210012 |
4 | 13201320002212030230002 |
5 | 13320020431300420114 |
6 | 154232250020504522 |
7 | 6655265525605655 |
oct | 741700246145402 |
9 | 140220572313705 |
10 | 33114241420034 |
11 | a607741aa4555 |
12 | 386991854b142 |
13 | 15628760b7a38 |
14 | 826a488a189c |
15 | 3c659db7763e |
hex | 1e1e0298cb02 |
33114241420034 has 16 divisors (see below), whose sum is σ = 51840551638080. Its totient is φ = 15834323237040.
The previous prime is 33114241420031. The next prime is 33114241420037. The reversal of 33114241420034 is 43002414241133.
It is an interprime number because it is at equal distance from previous prime (33114241420031) and next prime (33114241420037).
It is a super-2 number, since 2×331142414200342 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (33114241420031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66172097 + ... + 66670644.
It is an arithmetic number, because the mean of its divisors is an integer number (3240034477380).
Almost surely, 233114241420034 is an apocalyptic number.
33114241420034 is a deficient number, since it is larger than the sum of its proper divisors (18726310218046).
33114241420034 is a wasteful number, since it uses less digits than its factorization.
33114241420034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132848185.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 33114241420034 its reverse (43002414241133), we get a palindrome (76116655661167).
The spelling of 33114241420034 in words is "thirty-three trillion, one hundred fourteen billion, two hundred forty-one million, four hundred twenty thousand, thirty-four".
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