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331144134444113 is a prime number
BaseRepresentation
bin100101101001011001000000…
…0100000001100010001010001
31121102111001220002110011200012
41023102302000200030101101
5321400431141404202423
63132141303143204305
7126515242231401464
oct11322620040142121
91542431802404605
10331144134444113
1196570490a90671
1231181b50746695
13112a09b1106803
145bab6669a72db
152843c43a51078
hex12d2c8080c451

331144134444113 has 2 divisors, whose sum is σ = 331144134444114. Its totient is φ = 331144134444112.

The previous prime is 331144134444089. The next prime is 331144134444143. The reversal of 331144134444113 is 311444431441133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 296702588653249 + 34441545790864 = 17225057^2 + 5868692^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-331144134444113 is a prime.

It is not a weakly prime, because it can be changed into another prime (331144134444143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165572067222056 + 165572067222057.

It is an arithmetic number, because the mean of its divisors is an integer number (165572067222057).

Almost surely, 2331144134444113 is an apocalyptic number.

It is an amenable number.

331144134444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

331144134444113 is an equidigital number, since it uses as much as digits as its factorization.

331144134444113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 331776, while the sum is 41.

Adding to 331144134444113 its reverse (311444431441133), we get a palindrome (642588565885246).

The spelling of 331144134444113 in words is "three hundred thirty-one trillion, one hundred forty-four billion, one hundred thirty-four million, four hundred forty-four thousand, one hundred thirteen".