Base | Representation |
---|---|
bin | 100101101001011001000000… |
… | …0100000001100010001010001 |
3 | 1121102111001220002110011200012 |
4 | 1023102302000200030101101 |
5 | 321400431141404202423 |
6 | 3132141303143204305 |
7 | 126515242231401464 |
oct | 11322620040142121 |
9 | 1542431802404605 |
10 | 331144134444113 |
11 | 96570490a90671 |
12 | 31181b50746695 |
13 | 112a09b1106803 |
14 | 5bab6669a72db |
15 | 2843c43a51078 |
hex | 12d2c8080c451 |
331144134444113 has 2 divisors, whose sum is σ = 331144134444114. Its totient is φ = 331144134444112.
The previous prime is 331144134444089. The next prime is 331144134444143. The reversal of 331144134444113 is 311444431441133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 296702588653249 + 34441545790864 = 17225057^2 + 5868692^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331144134444113 is a prime.
It is not a weakly prime, because it can be changed into another prime (331144134444143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165572067222056 + 165572067222057.
It is an arithmetic number, because the mean of its divisors is an integer number (165572067222057).
Almost surely, 2331144134444113 is an apocalyptic number.
It is an amenable number.
331144134444113 is a deficient number, since it is larger than the sum of its proper divisors (1).
331144134444113 is an equidigital number, since it uses as much as digits as its factorization.
331144134444113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 331776, while the sum is 41.
Adding to 331144134444113 its reverse (311444431441133), we get a palindrome (642588565885246).
The spelling of 331144134444113 in words is "three hundred thirty-one trillion, one hundred forty-four billion, one hundred thirty-four million, four hundred forty-four thousand, one hundred thirteen".
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