Search a number
-
+
3311516151132 = 223722967103107263
BaseRepresentation
bin110000001100000101101…
…111100110110101011100
3102201120121020212101200020
4300030011233212311130
5413223441113314012
611013142311432140
7461151312565200
oct60140557466534
912646536771606
103311516151132
111067451599852
12455964085650
131b03754a4807
14b63c76a6b00
155b217e4aa8c
hex30305be6d5c

3311516151132 has 576 divisors, whose sum is σ = 9654373048320. Its totient is φ = 879465033216.

The previous prime is 3311516151109. The next prime is 3311516151169. The reversal of 3311516151132 is 2311516151133.

3311516151132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×33115161511323 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 3311516151093 and 3311516151102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 12591316033 + ... + 12591316295.

It is an arithmetic number, because the mean of its divisors is an integer number (16761064320).

Almost surely, 23311516151132 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3311516151132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4827186524160).

3311516151132 is an abundant number, since it is smaller than the sum of its proper divisors (6342856897188).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3311516151132 is a wasteful number, since it uses less digits than its factorization.

3311516151132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 590 (or 581 counting only the distinct ones).

The product of its digits is 8100, while the sum is 33.

Subtracting from 3311516151132 its reverse (2311516151133), we obtain a palindrome (999999999999).

The spelling of 3311516151132 in words is "three trillion, three hundred eleven billion, five hundred sixteen million, one hundred fifty-one thousand, one hundred thirty-two".