Base | Representation |
---|---|
bin | 110000001100100011010… |
… | …111101100111010011011 |
3 | 102201121212220011010222111 |
4 | 300030203113230322123 |
5 | 413231000334413201 |
6 | 11013303505133151 |
7 | 461166526464262 |
oct | 60144327547233 |
9 | 12647786133874 |
10 | 3312013201051 |
11 | 1067687120805 |
12 | 455a8262a1b7 |
13 | 1b0424465ba9 |
14 | b64336d15d9 |
15 | 5b2468ceb51 |
hex | 303235ece9b |
3312013201051 has 2 divisors, whose sum is σ = 3312013201052. Its totient is φ = 3312013201050.
The previous prime is 3312013201019. The next prime is 3312013201061. The reversal of 3312013201051 is 1501023102133.
It is a strong prime.
It is an emirp because it is prime and its reverse (1501023102133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3312013201051 - 25 = 3312013201019 is a prime.
It is not a weakly prime, because it can be changed into another prime (3312013201001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656006600525 + 1656006600526.
It is an arithmetic number, because the mean of its divisors is an integer number (1656006600526).
Almost surely, 23312013201051 is an apocalyptic number.
3312013201051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3312013201051 is an equidigital number, since it uses as much as digits as its factorization.
3312013201051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 3312013201051 its reverse (1501023102133), we get a palindrome (4813036303184).
The spelling of 3312013201051 in words is "three trillion, three hundred twelve billion, thirteen million, two hundred one thousand, fifty-one".
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