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3312104234113 = 20086916488877
BaseRepresentation
bin110000001100101000110…
…010111101110010000001
3102201122010020110002212101
4300030220302331302001
5413231142140442423
611013320520230401
7461202013321633
oct60145062756201
912648106402771
103312104234113
111067723548244
12455aa900b401
131b043a28a0cc
14b644182aa53
155b24e8b27ad
hex30328cbdc81

3312104234113 has 4 divisors (see below), whose sum is σ = 3312120923860. Its totient is φ = 3312087544368.

The previous prime is 3312104234111. The next prime is 3312104234203. The reversal of 3312104234113 is 3114324012133.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2946825423424 + 365278810689 = 1716632^2 + 604383^2 .

It is a cyclic number.

It is not a de Polignac number, because 3312104234113 - 21 = 3312104234111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3312104234111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8043570 + ... + 8445307.

It is an arithmetic number, because the mean of its divisors is an integer number (828030230965).

Almost surely, 23312104234113 is an apocalyptic number.

It is an amenable number.

3312104234113 is a deficient number, since it is larger than the sum of its proper divisors (16689747).

3312104234113 is a wasteful number, since it uses less digits than its factorization.

3312104234113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16689746.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 3312104234113 its reverse (3114324012133), we get a palindrome (6426428246246).

The spelling of 3312104234113 in words is "three trillion, three hundred twelve billion, one hundred four million, two hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 200869 16488877 3312104234113