Search a number
-
+
331211000113 = 747315857159
BaseRepresentation
bin1001101000111011011…
…01101100100100110001
31011122220122221002222021
410310131231230210301
520411310004000423
6412053425111441
732633501022640
oct4643555544461
91148818832867
10331211000113
11118513a7a674
1254235a88581
132530506a006
1412060341357
15893779795d
hex4d1db6c931

331211000113 has 4 divisors (see below), whose sum is σ = 378526857280. Its totient is φ = 283895142948.

The previous prime is 331211000089. The next prime is 331211000149. The reversal of 331211000113 is 311000112133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 331211000113 - 213 = 331210991921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (331211000173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23657928573 + ... + 23657928586.

It is an arithmetic number, because the mean of its divisors is an integer number (94631714320).

Almost surely, 2331211000113 is an apocalyptic number.

It is an amenable number.

331211000113 is a deficient number, since it is larger than the sum of its proper divisors (47315857167).

331211000113 is an equidigital number, since it uses as much as digits as its factorization.

331211000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47315857166.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 331211000113 its reverse (311000112133), we get a palindrome (642211112246).

The spelling of 331211000113 in words is "three hundred thirty-one billion, two hundred eleven million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 7 47315857159 331211000113