Base | Representation |
---|---|
bin | 110000001100101010011… |
… | …110001001001010000001 |
3 | 102201122012012022112022222 |
4 | 300030222132021022001 |
5 | 413231221334030423 |
6 | 11013323402340425 |
7 | 461202504200315 |
oct | 60145236111201 |
9 | 12648165275288 |
10 | 3312132330113 |
11 | 1067738398182 |
12 | 455ab64ba715 |
13 | 1b0443046569 |
14 | b6445461b45 |
15 | 5b2520b23c8 |
hex | 3032a789281 |
3312132330113 has 2 divisors, whose sum is σ = 3312132330114. Its totient is φ = 3312132330112.
The previous prime is 3312132330097. The next prime is 3312132330119. The reversal of 3312132330113 is 3110332312133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2058699823489 + 1253432506624 = 1434817^2 + 1119568^2 .
It is a cyclic number.
It is not a de Polignac number, because 3312132330113 - 24 = 3312132330097 is a prime.
It is not a weakly prime, because it can be changed into another prime (3312132330119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656066165056 + 1656066165057.
It is an arithmetic number, because the mean of its divisors is an integer number (1656066165057).
Almost surely, 23312132330113 is an apocalyptic number.
It is an amenable number.
3312132330113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3312132330113 is an equidigital number, since it uses as much as digits as its factorization.
3312132330113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 3312132330113 its reverse (3110332312133), we get a palindrome (6422464642246).
The spelling of 3312132330113 in words is "three trillion, three hundred twelve billion, one hundred thirty-two million, three hundred thirty thousand, one hundred thirteen".
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