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331220242022134 = 22833338917249191
BaseRepresentation
bin100101101001111100011100…
…0110111100011111011110110
31121102202100100011021201112011
41023103320320313203323312
5321403203023424202014
63132240251212514434
7126523605240213163
oct11323707067437366
91542670304251464
10331220242022134
119659a796800483
1231194850a7ba1a
13112a7c1c9b4a4a
145bb12067d306a
152845bea4497c4
hex12d3e38de3ef6

331220242022134 has 16 divisors (see below), whose sum is σ = 497152417001760. Its totient is φ = 165502804199040.

The previous prime is 331220242022129. The next prime is 331220242022149. The reversal of 331220242022134 is 431220242022133.

It is a junction number, because it is equal to n+sod(n) for n = 331220242022096 and 331220242022105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10577479 + ... + 27826669.

It is an arithmetic number, because the mean of its divisors is an integer number (31072026062610).

Almost surely, 2331220242022134 is an apocalyptic number.

331220242022134 is a deficient number, since it is larger than the sum of its proper divisors (165932174979626).

331220242022134 is a wasteful number, since it uses less digits than its factorization.

331220242022134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17255415.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 331220242022134 its reverse (431220242022133), we get a palindrome (762440484044267).

Subtracting 331220242022134 from its reverse (431220242022133), we obtain a palindrome (99999999999999).

The spelling of 331220242022134 in words is "three hundred thirty-one trillion, two hundred twenty billion, two hundred forty-two million, twenty-two thousand, one hundred thirty-four".

Divisors: 1 2 2833 3389 5666 6778 9601037 17249191 19202074 34498382 48866958103 58457508299 97733916206 116915016598 165610121011067 331220242022134