Base | Representation |
---|---|
bin | 100101101001111100011111… |
… | …0000111101000001110110001 |
3 | 1121102202100120022001120020021 |
4 | 1023103320332013220032301 |
5 | 321403203214002320423 |
6 | 3132240304041043441 |
7 | 126523610360064460 |
oct | 11323707607501661 |
9 | 1542670508046207 |
10 | 331220330120113 |
11 | 9659a831502825 |
12 | 31194876486581 |
13 | 112a7c3501c025 |
14 | 5bb12143a69d7 |
15 | 2845c0304c95d |
hex | 12d3e3e1e83b1 |
331220330120113 has 8 divisors (see below), whose sum is σ = 391590538073280. Its totient is φ = 274113376650960.
The previous prime is 331220330120111. The next prime is 331220330120123. The reversal of 331220330120113 is 311021033022133.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 331220330120113 - 21 = 331220330120111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (331220330120111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 815813620783 + ... + 815813621188.
It is an arithmetic number, because the mean of its divisors is an integer number (48948817259160).
Almost surely, 2331220330120113 is an apocalyptic number.
It is an amenable number.
331220330120113 is a deficient number, since it is larger than the sum of its proper divisors (60370207953167).
331220330120113 is a wasteful number, since it uses less digits than its factorization.
331220330120113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1631627242007.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 331220330120113 its reverse (311021033022133), we get a palindrome (642241363142246).
The spelling of 331220330120113 in words is "three hundred thirty-one trillion, two hundred twenty billion, three hundred thirty million, one hundred twenty thousand, one hundred thirteen".
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