331231013000113 has 4 divisors (see below), whose sum is σ = 334446848077888. Its totient is φ = 328015177922340.

The previous prime is 331231013000039. The next prime is 331231013000141. The reversal of 331231013000113 is 311000310132133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-331231013000113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (331231013000183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1607917538733 + ... + 1607917538938.

It is an arithmetic number, because the mean of its divisors is an integer number (83611712019472).

Almost surely, 2^{331231013000113} is an apocalyptic number.

It is an amenable number.

331231013000113 is a deficient number, since it is larger than the sum of its proper divisors (3215835077775).

331231013000113 is a wasteful number, since it uses less digits than its factorization.

331231013000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3215835077774.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 331231013000113 its reverse (311000310132133), we get a palindrome (642231323132246).

The spelling of 331231013000113 in words is "three hundred thirty-one trillion, two hundred thirty-one billion, thirteen million, one hundred thirteen", and thus it is an aban number.