Base | Representation |
---|---|
bin | 110000001101011110010… |
… | …000101000000101100111 |
3 | 102201201102202020210112002 |
4 | 300031132100220011213 |
5 | 413240011301431043 |
6 | 11013545521315515 |
7 | 461233154401502 |
oct | 60153620500547 |
9 | 12651382223462 |
10 | 3313001202023 |
11 | 1068043899537 |
12 | 4560b9495b9b |
13 | 1b0551061656 |
14 | b64c89d8139 |
15 | 5b2a34e0bb8 |
hex | 3035e428167 |
3313001202023 has 16 divisors (see below), whose sum is σ = 3526724124000. Its totient is φ = 3103217137152.
The previous prime is 3313001201981. The next prime is 3313001202059. The reversal of 3313001202023 is 3202021003133.
It is a cyclic number.
It is not a de Polignac number, because 3313001202023 - 26 = 3313001201959 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3313001201986 and 3313001202004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3313001202323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51558611 + ... + 51622827.
It is an arithmetic number, because the mean of its divisors is an integer number (220420257750).
Almost surely, 23313001202023 is an apocalyptic number.
3313001202023 is a deficient number, since it is larger than the sum of its proper divisors (213722921977).
3313001202023 is a wasteful number, since it uses less digits than its factorization.
3313001202023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94834.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 3313001202023 its reverse (3202021003133), we get a palindrome (6515022205156).
The spelling of 3313001202023 in words is "three trillion, three hundred thirteen billion, one million, two hundred two thousand, twenty-three".
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